Bash find & replace using regex pipe

Find & replace using regex on the command line using perl.

perl -pe "s/find/replace/g"

Parentheses for grouping and capturing is also supported.

$ echo "myfile.txt" | perl -pe "s/(.*)\.txt/\1.log/"
myfile.log

$ find=".*(\d{4})\/(\d{2})\/(\d{2})\/.*"
$ replace="year: \1; month: \2; day: \3"
$ echo "https://www.example.com/2014/04/28/page-slug" | perl -pe "s/${find}/${replace}/"
year: 2014; month: 04; day: 28